вправа 11.1 гдз 10 клас математика Мерзляк Номіровський 2018
Вправа 11.1
Умова:
Умова:
Знайдіть значення виразу.
Відповідь ГДЗ:
\begin{equation} 1) \sin 390^{\circ} = \end{equation} \begin{equation} =\sin (390^{\circ}+30)= \end{equation} \begin{equation} = \sin 30=\frac{1}{2}; \end{equation} \begin{equation} 2) tg \, 780^{\circ}= \end{equation} \begin{equation} =tg(360^{\circ} \cdot 2+60^{\circ})= \end{equation} \begin{equation} =tg \, 60^{\circ}=\sqrt{3}; \end{equation} \begin{equation} 3) \sin (-390^{\circ})= \end{equation} \begin{equation} =-\sin (360+30)= \end{equation} \begin{equation} =- \sin 80^{\circ}=-\frac{1}{2}; \end{equation} \begin{equation} 4) \, tg(-210^{\circ})=- \end{equation} \begin{equation} =tg(180^{\circ}+30^{\circ})= \end{equation} \begin{equation} =-tg \, 30^{\circ}=-\frac{\sqrt{3}}{3}; \end{equation} \begin{equation} 5) \cos 300^{\circ}= \end{equation} \begin{equation} =\cos (360^{\circ}-60^{\circ})= \end{equation} \begin{equation} = \cos (-60^{\circ})= \end{equation} \begin{equation} =\cos 60^{\circ}=\frac{1}{2}; \end{equation} \begin{equation} 6) \sin \frac{5 \pi}{3}= \end{equation} \begin{equation} =\sin \left ( 2 \pi -\frac{\pi }{3} \right )= \end{equation} \begin{equation} =\sin \left (-\frac{\pi }{3} \right )= \end{equation} \begin{equation} =-\sin \frac{\pi }{3}=-\frac{\sqrt{3}}{2}. \end{equation}
\begin{equation} 1) \sin 390^{\circ} = \end{equation} \begin{equation} =\sin (390^{\circ}+30)= \end{equation} \begin{equation} = \sin 30=\frac{1}{2}; \end{equation} \begin{equation} 2) tg \, 780^{\circ}= \end{equation} \begin{equation} =tg(360^{\circ} \cdot 2+60^{\circ})= \end{equation} \begin{equation} =tg \, 60^{\circ}=\sqrt{3}; \end{equation} \begin{equation} 3) \sin (-390^{\circ})= \end{equation} \begin{equation} =-\sin (360+30)= \end{equation} \begin{equation} =- \sin 80^{\circ}=-\frac{1}{2}; \end{equation} \begin{equation} 4) \, tg(-210^{\circ})=- \end{equation} \begin{equation} =tg(180^{\circ}+30^{\circ})= \end{equation} \begin{equation} =-tg \, 30^{\circ}=-\frac{\sqrt{3}}{3}; \end{equation} \begin{equation} 5) \cos 300^{\circ}= \end{equation} \begin{equation} =\cos (360^{\circ}-60^{\circ})= \end{equation} \begin{equation} = \cos (-60^{\circ})= \end{equation} \begin{equation} =\cos 60^{\circ}=\frac{1}{2}; \end{equation} \begin{equation} 6) \sin \frac{5 \pi}{3}= \end{equation} \begin{equation} =\sin \left ( 2 \pi -\frac{\pi }{3} \right )= \end{equation} \begin{equation} =\sin \left (-\frac{\pi }{3} \right )= \end{equation} \begin{equation} =-\sin \frac{\pi }{3}=-\frac{\sqrt{3}}{2}. \end{equation}