вправа 4.35 гдз 11 клас алгебра Істер 2019
Вправа 4.35
Умова:
Обчисліть:
1) log131/5√132; 2) log27tgπ/3; 3) log√8(16√2); 4) log323√2.
1) log131/5√132; 2) log27tgπ/3; 3) log√8(16√2); 4) log323√2.
Відповідь:
1) log131/5√132 = log1313-2/5 = -2/5;
2) log27tgπ/3 = log33√3 = log3331/2 = 1/6log33 = 1/6;
3) log√8(16√2) = log23/224 • 21/2 = 2/3log2241/2 = 2/3 • 3/2log22 = 3;
4) log323√2 = log2521/3 = 1/5 • 1/3 • log22 = 1/15.
2) log27tgπ/3 = log33√3 = log3331/2 = 1/6log33 = 1/6;
3) log√8(16√2) = log23/224 • 21/2 = 2/3log2241/2 = 2/3 • 3/2log22 = 3;
4) log323√2 = log2521/3 = 1/5 • 1/3 • log22 = 1/15.