вправа 5.9 гдз 11 клас алгебра Істер 2019
Вправа 5.9
Умова:
Дано: g(x) = log1/3x. Знайдіть:
1) g(1); 2) g(1/9); 3) g(1/3); 4) g(81).
1) g(1); 2) g(1/9); 3) g(1/3); 4) g(81).
Відповідь:
g(x) = log1/3x
1) g(1) - ?
g(1) = log1/31 = 0;
2) g(1/9) - ?
g(1/9) = log1/3(1/9) = log1/3(1/3)2 = 2log1/3(1/3) = 2;
3) g(1/3) - ?
g(1/3) = log1/3(1/3) = 1;
4) g(81) = ?
g(81) = log1/381 = log1/334 = log1/3(1/3)-4 = -4log1/31/3 = -4.
1) g(1) - ?
g(1) = log1/31 = 0;
2) g(1/9) - ?
g(1/9) = log1/3(1/9) = log1/3(1/3)2 = 2log1/3(1/3) = 2;
3) g(1/3) - ?
g(1/3) = log1/3(1/3) = 1;
4) g(81) = ?
g(81) = log1/381 = log1/334 = log1/3(1/3)-4 = -4log1/31/3 = -4.