Вправа 1232 гдз 5 клас математика О. С. Істер 2022 НУШ

Завдання 1232.
Розв'яжи рівняння: $$
\begin{aligned}
& \text { 1) }\left(\frac{12}{31}+x\right)-\frac{7}{31}=\frac{19}{31} \\
& \frac{12}{31}+x=\frac{19}{31}+\frac{7}{31} \\
& \frac{12}{31}+x=\frac{26}{31} \\
& x=\frac{26}{31}-\frac{12}{31} \\
& x=\frac{14}{31}
\end{aligned}
$$
$$
\begin{aligned}
& \text { 2) } \frac{18}{43}-\left(x-\frac{14}{43}\right)=\frac{9}{43} \\
& x-\frac{14}{43}=\frac{18}{43}-\frac{9}{43} \\
& x-\frac{14}{43}=\frac{9}{43} \\
& x=\frac{9}{43}+\frac{14}{43} \\
& x=\frac{23}{43}
\end{aligned}
$$
$$
\begin{aligned}
& \text { 3) } \frac{34}{37}-\left(x+\frac{12}{37}\right)=\frac{22}{37} \\
& x+\frac{12}{37}=\frac{34}{37}-\frac{22}{37} \\
& x+\frac{12}{37}=\frac{12}{37} \\
& x=\frac{12}{37}-\frac{12}{37} \\
& x=0
\end{aligned}
$$ $$
\begin{aligned}
& \text { 4) }\left(x+\frac{12}{37}\right)+\frac{4}{37}=\frac{17}{37} \\
& x+\frac{12}{37}=\frac{17}{37}-\frac{4}{37} \\
& x+\frac{12}{37}=\frac{13}{37} \\
& x=\frac{13}{37}-\frac{12}{37} \\
& x=\frac{1}{37}
\end{aligned}
$$
$$
\text { 5) }\left(x-\frac{5}{29}\right)+\frac{4}{29}=\frac{4}{29}
$$
$$
x-\frac{5}{29}=\frac{4}{29}-\frac{4}{29}
$$
$$
x-\frac{5}{29}=0
$$
$$
x=0+\frac{5}{29}
$$
$$
x=\frac{5}{29}
$$
$$
\begin{aligned}
& \text { 6) } \frac{15}{59}+\left(\frac{27}{59}-x\right)=\frac{17}{59} \\
& \frac{27}{59}-x=\frac{17}{59}-\frac{15}{59} \\
& \frac{27}{59}-x=\frac{2}{59} \\
& x=\frac{27}{59}-\frac{2}{59} \\
& x=\frac{25}{59}
\end{aligned}
$$