Вправа 1267 гдз 5 клас математика О. С. Істер 2022 НУШ

Завдання 1267
Виконай діi: $$
\begin{aligned}
& \text { 1) }\left(7-2 \frac{3}{11}\right)+4 \frac{10}{11}=7+\left(4 \frac{10}{11}-2 \frac{3}{11}\right)= \\
& =7+2 \frac{7}{11}=9 \frac{7}{11}
\end{aligned}
$$ 2) $12 \frac{1}{7}-\left(5 \frac{4}{7}+3 \frac{6}{7}\right)=12 \frac{1}{7}-8 \frac{10}{7}=$ $$
=12 \frac{1}{7}-9 \frac{3}{7}=11 \frac{8}{7}-9 \frac{3}{7}=2 \frac{5}{7}
$$
$$
\text { 3) } \begin{aligned}
& \left(5 \frac{6}{7}-3 \frac{2}{7}\right)-\left(9 \frac{3}{7}-8 \frac{4}{7}\right)= \\
= & 2 \frac{4}{7}-\left(8 \frac{10}{7}-8 \frac{4}{7}\right)=2 \frac{4}{7}-\frac{6}{7}= \\
= & 1 \frac{11}{7}-\frac{6}{7}=1 \frac{5}{7}
\end{aligned}
$$ 4) $\left(5 \frac{1}{4}+3 \frac{3}{4}\right)-4 \frac{2}{17}=8 \frac{4}{4}-4 \frac{2}{17}=$ $$
=9-4 \frac{2}{17}=8 \frac{17}{17}-4 \frac{2}{17}=4 \frac{15}{17}
$$ 5) $\left(9 \frac{18}{17}-5 \frac{8}{17}\right)-\left(1 \frac{12}{13}+1 \frac{8}{13}\right)=$ $$
=4-2 \frac{20}{13}=4-3 \frac{7}{13}=3 \frac{13}{13}-3 \frac{7}{13}=\frac{6}{13}
$$
$$
\begin{aligned}
& \text { 6) }\left(19 \frac{3}{19}-7 \frac{16}{19}\right)-\left(4 \frac{5}{8}+3 \frac{3}{8}\right)= \\
& =\left(18 \frac{22}{19}-7 \frac{16}{19}\right)-7 \frac{8}{8}=11 \frac{6}{19}-8=3 \frac{6}{19}
\end{aligned}
$$