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Вправа 417 алгебра Бевз гдз 7 клас

№ 417

  1. a) a(a2 + 1) + 5(a2 + 1) = (a2 + 1)(a + 5);
    б) 8(a2 – 3) + (a2 – 3)2 = (a2 – 3)(8 + a2 – 3);
    в) 5b(3 + 2c)3 + 2b(3 + 2c)2 = b(3 + 2c)(15 + 10c + 2b);
    г) x(a – b) + 3y(b – a) = (a – b)(x – 3y);
    ґ) 4(b – 3) + 5b(3 – b) = (b – 3)(4 – 5b);
    д) 7(a – 4)2 + (4 – a) = (a – 4)(7a – 28 – 1) = (a – 4)(7a – 29);
    e) 5a(3a – b) + (b – 3a)(5a + 2b) = (3a – b)(5a – 5a – 2b) =
    = –2b(3a – b);
    є) (a + 7b)(a – 5b) – (b – 3a)(a – 5b) = (a – 5b)(a + 7b – b + 3a) =
    = (a – 5b)(4b + 6b).

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