Вправа 422 алгебра Бевз гдз 7 клас
\begin{equation}\begin{aligned}
&\text { № } 422\\
&\begin{aligned}
& \text { a) } 2(3 x-2)^2-(2-3 x)=0 \\
& (3 x-2)(6 x-4+1)=0 \\
& \begin{array}{ll}
\text { 1) } 3 x-2=0 & \text { 2) } 6 x-3=0 \\
3 x=2 & 6 x=3 \\
x_1=\frac{2}{3} & x_2=2
\end{array}
\end{aligned}\\
&\begin{aligned}
& \text { б) } x^2-5(x-3)=15 \\
& x^2-5 x+15=15 \\
& x_1=0 ; x_2=5
\end{aligned}\\
&\begin{aligned}
& \text { в) } 2 z^4-7\left(z^3-3\right)=21 \\
& 2 z^4-7 z^3+21=21 \\
& z^3(2 z-7)=0 \\
& z_1=0 \\
& 2 z=7 \\
& z_2=3,5
\end{aligned}\\
&\begin{aligned}
& \text { г) } 2 z^4-\frac{1}{3} z\left(6 z^2-3\right)=z \\
& 2 z^4-2 z^3+z=z \\
& 2 z^3(z-1)=0 \\
& z_1=0 \\
& z_2=1
\end{aligned}
\end{aligned}
\end{equation}
вправи поруч
