№ 520
а) (x + 1)3 = x3 + 3x2 – 2x3 + 3x2 + 3x + 1 – x3 – 3x2 = –23x = –3x = –1;б) (x + 2)3 – 6x2 = (x + 2)(x2 – 2x + 4)x3 + 6x2 + 12x + 8 – 6x2 = x3 + 812x = 0x = 0.
вправи поруч