№ 1052a) (2;1)(2 ; 1)(2;1){x+y=3x−y=1 \left\{\begin{array}{l} x+y=3 \\ x-y=1 \end{array}\right. {x+y=3x−y=1б) (−3;2)(-3 ; 2)(−3;2){x+y=−1x−y=−5 \left\{\begin{array}{l} x+y=-1 \\ x-y=-5 \end{array}\right. {x+y=−1x−y=−5в) (5;0)(5 ; 0)(5;0){x+y=5x−y=5 \left\{\begin{array}{l} x+y=5 \\ x-y=5 \end{array}\right. {x+y=5x−y=5 г) (0;−4){x+y=−4x−y=4 \begin{aligned} & \text { г) }(0 ;-4) \\ & \left\{\begin{array}{c} x+y=-4 \\ x-y=4 \end{array}\right. \end{aligned} г) (0;−4){x+y=−4x−y=4
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