Вправа 557 алгебра Бевз гдз 7 клас
$$\begin{aligned}
&\text { № } 557\\
&\begin{aligned}
& (2+1) \cdot\left(2^2+1\right) \cdot\left(2^4+1\right) \cdot\left(2^8+1\right) \cdot\left(2^{16}+1\right)-2^{32}= \\
& (2+1) \cdot(2-1) \cdot\left(2^2+1\right) \cdot\left(2^4+1\right) \cdot\left(2^8+1\right) \cdot\left(2^{16}+1\right)-2^{32}= \\
& \left(2^2-1\right) \cdot\left(2^2+1\right) \cdot\left(2^4+1\right) \cdot\left(2^8+1\right) \cdot\left(2^{16}+1\right)-2^{32}= \\
& \left(2^4-1\right) \cdot\left(2^4+1\right) \cdot\left(2^8+1\right) \cdot\left(2^{16}+1\right)-2^{32}= \\
& \left(2^8-1\right) \cdot\left(2^8+1\right) \cdot\left(2^{26}+1\right)-2^{32}= \\
& \left(2^{16}-1\right) \cdot\left(2^{16}+1\right)-2^{32}=2^{32}-1-2^{32}=-1 .
\end{aligned}
\end{aligned}
$$
вправи поруч
