Вправа 582 алгебра Бевз гдз 7 клас
№ 582а) $a^3-c^3=(a-c)\left(a^2+a c+c^2\right)$;
б) $x^3+8=(x+2)\left(x^2-2 x+4\right)$;
в) $1-p^3=(1-p)\left(1+p+p^2\right)$;
г) $c^3-64 x^3=(c-4 x)\left(c^2+4 c x+16 x^2\right)$; ґ) $n^6-1=\left(n^2-1\right)\left(n^4+n^2+1\right)$;
д) $27 a^3+b^3=(3 a+b)\left(9 a^2-3 a b+b^2\right)$;
e) $a^3-8 m^3 n^3=(a-2 m n)\left(a^2+2 a m+4 m^2 n^2\right)$; є) $-z^3-p^3=-(z+p)\left(z^2-z p+p^3\right)$;
ж) $\frac{1}{125}+\mathrm{y}^3 \mathrm{z}^9=\left(\frac{1}{5}+\mathrm{yz}^3\right)\left(\frac{1}{25}-\frac{1}{5} \mathrm{yz}^3+6\right)$;
з) $\frac{1}{8}+\mathrm{c}^3=\left(\frac{1}{2}+\mathrm{c}\right)\left(\frac{1}{4}-\frac{1}{2} \mathrm{c}+\mathrm{c}^2\right)$;
и) $\frac{8}{27} \mathrm{x}^3+1=\left(\frac{2}{3} \mathrm{x}+1\right)\left(\frac{4}{9} \mathrm{x}^2-\frac{2}{3} \mathrm{x}+1\right)$;
i) $\frac{27}{64}+z^3=\left(\frac{3}{4}+z\right)\left(\frac{9}{16}-\frac{3}{4} z+z^2\right)$.
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