вправа 1053 гдз 7 клас алгебра Мерзляк Полонський
7 клас ➠ алгебра ➠ Мерзляк Полонський
Вправа 1053
Відповідь:
\begin{equation}1)\left\{\begin{matrix}
\left ( x-3 \right )^{2}-4y=\\
=\left ( x+2 \right )\left ( x+1 \right )-6,\\
\left ( x-4 \right )\left ( y+6 \right )=\\
=\left ( x+3 \right ) \left ( y-7 \right )+3;
\end{matrix}\right.
\end{equation}
\begin{equation}\left\{\begin{matrix}
x^{2}-6x+9-4y=\\
=x^{2}+3x+2-6,\\
xy+6x-4y-24=\\
=xy-7x+3y-21+3;
\end{matrix}\right.
\end{equation}
\begin{equation}\left\{\begin{matrix}
-9x-4y=-13,\\ 13x-7y=6;
\end{matrix}\right.
\end{equation}
\begin{equation}+\left\{\begin{matrix}
63x+28y=91,\\ 52x-28y=24;
\end{matrix}\right.
\end{equation}
\begin{equation}\left\{\begin{matrix}
115x=115,\\ 4y=13-9x;
\end{matrix}\right.
\end{equation}
\begin{equation}\left\{\begin{matrix}
x=1,\\ y=1;
\end{matrix}\right.
\end{equation}
\begin{equation}2)\left\{\begin{matrix}
\left ( x-y \right )\left ( x+y \right )-x\left ( x+10 \right )=\\
=y\left ( 5-y \right )+15,\\
\left ( x+1 \right )^{2}+\left ( y-1 \right ) ^{2}=\\
=\left ( x+4 \right )^{2}+\left ( y+2 \right )^{2}-18;
\end{matrix}\right.
\end{equation}
\begin{equation}\left\{\begin{matrix}
x^{2}-y^{2}-x^{2}-10x=\\
=5y-y^{2}+15,
\\x^{2}+2x+1+\\
+y^{2}-2y+1=\\
=x^{2}+8x+16+y^{2}+\\
+4y+4-18;
\end{matrix}\right.
\end{equation}
\begin{equation}\left\{\begin{matrix}
10x+5y=-15,\\-6x-6y=0;
\end{matrix}\right.
\end{equation}
\begin{equation}\left\{\begin{matrix}
2x+y=-3,\\x=-y;
\end{matrix}\right.
\end{equation}
\begin{equation}\left\{\begin{matrix}
-2y+y=-3,\\x=-y;
\end{matrix}\right.
\end{equation}
\begin{equation}\left\{\begin{matrix}
y=3,\\x=-3.
\end{matrix}\right.
\end{equation}