вправа 529 гдз 7 клас алгебра Мерзляк Полонський
7 клас ➠ алгебра ➠ Мерзляк Полонський
Вправа 529
Відповідь:
\begin{equation}1)\frac{4x-1}{12}-\frac{3x+1}{8}=x+1;\end{equation}
\begin{equation}\frac{2\cdot \left ( 4x-1 \right )}{24}-\frac{3\cdot \left ( 3x+1 \right )}{24}=\end{equation}
\begin{equation}=\frac{24\cdot \left ( x+1 \right )}{24};\end{equation}
8x - 2 - 9x - 3 = 24x + 24;
25x = -29; \begin{equation}x=-\frac{29}{25}=-1\frac{4}{25};\end{equation} \begin{equation}2)\frac{3x-2}{9}-\frac{2x+1}{6}=\frac{5-x}{3};\end{equation} \begin{equation}\frac{2\cdot \left ( 3x-2 \right )}{18}-\frac{3\cdot \left ( 2x+1 \right )}{18}=\end{equation} \begin{equation}=\frac{6\cdot \left ( 5-x \right )}{18};\end{equation} 6x - 4 - 6x - 3 = 30 - 6x;
6x = 37; \begin{equation}x=\frac{37}{6}=6\frac{1}{6}.\end{equation}
25x = -29; \begin{equation}x=-\frac{29}{25}=-1\frac{4}{25};\end{equation} \begin{equation}2)\frac{3x-2}{9}-\frac{2x+1}{6}=\frac{5-x}{3};\end{equation} \begin{equation}\frac{2\cdot \left ( 3x-2 \right )}{18}-\frac{3\cdot \left ( 2x+1 \right )}{18}=\end{equation} \begin{equation}=\frac{6\cdot \left ( 5-x \right )}{18};\end{equation} 6x - 4 - 6x - 3 = 30 - 6x;
6x = 37; \begin{equation}x=\frac{37}{6}=6\frac{1}{6}.\end{equation}