вправа 1038 гдз 7 клас алгебра Мерзляк Полонський

7 клас ➠ алгебра ➠ Мерзляк Полонський


Вправа 1038

 

Відповідь: \begin{equation}1)\left\{\begin{matrix} 6-5\left ( x-y \right )=7x+4y,\\ 3\left ( x+1 \right )-\left ( 6x+8y \right )=69+3y; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} -12x+y=-6,\\ -3x-11y=66; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} y=12x-6,\\ -3x-11\left ( 12x-6 \right )=66; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} y=12x-6,\\ -3x-132x+66=66; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} y=-6,\\ x=0; \end{matrix}\right. \end{equation} \begin{equation}2)\left\{\begin{matrix} \frac{x}{2}-\frac{y}{3}=2,\\5x-y=34; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} 3x-2y=12,\\ 5x-y=34; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} 3x-2\left ( 5x-34 \right )=12,\\ y=5x-34; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} 3x-10x+68=12,\\ y=5x-34; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} -7x=-56,\\ y=5x-34; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} x=8,\\ y=6; \end{matrix}\right. \end{equation} \begin{equation}3)\left\{\begin{matrix} 6y-5x=1,\\ \frac{x-1}{2}+\frac{3y-x}{4}=-4\frac{3}{4}; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} 6x-5y=1,\\\frac{2\left ( x-1 \right )}{4}+\frac{3y-x}{4}=-\frac{19}{4}; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} 6y-5x=1,\\ x+3y=-17; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} 6y+5\left ( 17+3y \right )=1,\\x=-17-3y; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} 6y+85+15y=1,\\ x=-17-3y; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} 21y=-84,\\ x=-17-3y; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} y=-4,\\ x=-5; \end{matrix}\right. \end{equation} \begin{equation}4)\left\{\begin{matrix} \frac{1,5x-3}{3}+\frac{7-3y}{8}=3,\\ \frac{2,5x-2}{3}-\frac{2y+1}{6}=x-0,5; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} 8\left ( 1,5x-3 \right )+3\left ( 7-3y \right )=72,\\ 2\left ( 2,5x-2 \right )-\left ( 2y+1 \right )=6x-3; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} 12x-24+21-9y=72,\\5x-4-2y-1=6x-3; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} 12x-9y=75,\\-x-2y=2; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} 4x-3y=25,\\x=-2y-2; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} 4\left ( -2y-2 \right )-3y=25,\\ x=-2y-2; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} -11y=33,\\ x=-2y-2; \end{matrix}\right. \end{equation} \begin{equation}\left\{\begin{matrix} y=-3,\\ x=4. \end{matrix}\right. \end{equation}