Вправа 453 алгебра Бевз гдз 7 клас

№ 453

а) ax² + bx² – cx² + am + bm – cm = x²(a + b – c) + m(a + b – c) =
= (a + b – c)(x² + m);
б) a + b + ax² + bx² – bx – ax = (a + ax² – ax) + (b + bx² – bx) =
= a(1 + x² – x) + b(1 + x² – x) = (1 + x² – x)(a + b)
в) 2am + 3mx – 7m – 2ac – 6cx + 7c = (2am – 2ac) + (3mx – 3cx) – (7m – 3c) = 2a(m – c) + 3x(m – c) – 7(m – c) =
= (m – c)(2a + 3x – 7)
г) 4ax² – ax + 5a – 4bx² + bx – 5b = (4ax² – 4bx²) + (5a – 5b) –
– (ax – bx) = 4x² (a – b) + 5(a – b) – x(a – b) = (a – b)(4x² + 5 – x).