вправа 1156 гдз 7 клас алгебра Мерзляк Полонський

Відповідь: \begin{equation}1)\frac{3x-1}{6}-\frac{x}{3}=\end{equation} \begin{equation}=\frac{5-2x}{9};\end{equation} \begin{equation}\frac{3\left ( 3x-1 \right )}{18}-\frac{6x}{18}=\end{equation} \begin{equation}=\frac{2\left ( 5-2x \right )}{18};\end{equation} 9x - 3 - 6x = 10 - 4x;
7x = 13; \begin{equation}x=\frac{13}{7}=1\frac{6}{7};\end{equation} \begin{equation}2)\frac{3x+1}{2}-\frac{5x}{4}=\end{equation} \begin{equation}=\frac{3-2x}{3};\end{equation} \begin{equation}\frac{6\left ( 3x+1 \right )}{12}-\frac{15x}{12}=\end{equation} \begin{equation}=\frac{4\left ( 3-2x \right )}{12};\end{equation} 18x + 6 - 15x = 12 - 8x;
11x = 6; \begin{equation}x=\frac{6}{11};\end{equation} \begin{equation}3)\frac{x+5}{8}-\frac{1+x}{2}=\end{equation} \begin{equation}=\frac{2x+1}{3};\end{equation} \begin{equation}\frac{3\left ( x+5 \right )}{24}-\frac{12\left ( 1+x \right )}{24}=\end{equation} \begin{equation}=\frac{8\left ( 2x+1 \right )}{24};\end{equation} 3x + 15 - 12 - 12x = 16x + 8;
-25x = 5;
x = -0,2; \begin{equation}4)\frac{2x}{3}-\frac{2x+1}{6}=\frac{3x-9}{4};\end{equation} \begin{equation}\frac{16x}{24}-\frac{4\left ( 2x+1 \right )}{24}=\end{equation} \begin{equation}=\frac{6\left ( 3x-9 \right )}{24};\end{equation} 16x - 8x - 4 = 18x - 54;
-10x = -50;
x = 5; \begin{equation}5)\frac{9x-7}{4}-\frac{9x+13}{8}=;\end{equation} \begin{equation}=\frac{3-x}{2}\end{equation} \begin{equation}\frac{2\left ( 9x-7 \right )}{8}-\frac{9x+13}{8}=\end{equation} \begin{equation}=\frac{4\left ( 3-x \right )}{8};\end{equation} 18x - 14 - 9x - 13 = 12 - 4x;
13x = 39;
x = 3; \begin{equation}6)\frac{6x+7}{6}+\frac{5x-8}{9}=3;\end{equation} \begin{equation}\frac{3\left ( 6x+7 \right )}{18}+\frac{2\left ( 5x-8 \right )}{18}=\end{equation} \begin{equation}=\frac{54}{18};\end{equation} 18x + 21 + 10x - 16 = 54;
28x = 49; \begin{equation}x=\frac{7}{4}=1\frac{3}{4}.\end{equation}