вправа 948 гдз 7 клас алгебра Мерзляк Полонський
7 клас ➠ алгебра ➠ Мерзляк Полонський
Вправа 948
Відповідь:
3m²n = 2; \begin{equation}n^{2}k^{4}=3.\end{equation} \begin{equation}m²n=\frac{2}{3}.\end{equation} \begin{equation}1)\left ( 3m^{2}n^{2}k^{2} \right )^{2}=\end{equation} \begin{equation}=\left ( 3m^{2}n \right )^{2}\cdot \left ( nk^{2} \right )^{2}=\end{equation} \begin{equation}=2^{2}\cdot n^{2}k^{4}=4\cdot 3=12;\end{equation} \begin{equation}2)\left ( -2m^{2}nk^{2} \right )^{3}\cdot \left ( 0,5n^{2}k \right )^{2}=\end{equation} \begin{equation}=\left ( -2\cdot \frac{2}{3}\cdot k^{2} \right )^{3}\cdot \frac{1}{4}n^{4}k^{2}=\end{equation} \begin{equation}=-\frac{64}{27}k^{6}\cdot \frac{1}{4}n^{4}k^{2}=\end{equation} \begin{equation}=-\frac{16}{27}n^{4}k^{8}=\end{equation} \begin{equation}=-\frac{16}{27}\left ( n^{2}k^{4} \right )^{2}=\end{equation} \begin{equation}=-\frac{16}{27}\cdot 3^{2}=-\frac{16}{3}.\end{equation}
3m²n = 2; \begin{equation}n^{2}k^{4}=3.\end{equation} \begin{equation}m²n=\frac{2}{3}.\end{equation} \begin{equation}1)\left ( 3m^{2}n^{2}k^{2} \right )^{2}=\end{equation} \begin{equation}=\left ( 3m^{2}n \right )^{2}\cdot \left ( nk^{2} \right )^{2}=\end{equation} \begin{equation}=2^{2}\cdot n^{2}k^{4}=4\cdot 3=12;\end{equation} \begin{equation}2)\left ( -2m^{2}nk^{2} \right )^{3}\cdot \left ( 0,5n^{2}k \right )^{2}=\end{equation} \begin{equation}=\left ( -2\cdot \frac{2}{3}\cdot k^{2} \right )^{3}\cdot \frac{1}{4}n^{4}k^{2}=\end{equation} \begin{equation}=-\frac{64}{27}k^{6}\cdot \frac{1}{4}n^{4}k^{2}=\end{equation} \begin{equation}=-\frac{16}{27}n^{4}k^{8}=\end{equation} \begin{equation}=-\frac{16}{27}\left ( n^{2}k^{4} \right )^{2}=\end{equation} \begin{equation}=-\frac{16}{27}\cdot 3^{2}=-\frac{16}{3}.\end{equation}