ГДЗ з алгебри 8 клас Істер, вправа №3.4

1) $\frac{7a-3a}{4x}=\frac{4a}{4x}=\frac{a}{x}$

2) $\frac{x+y-(x-3y)}{8}=\frac{4y}{8}=\frac{y}{2}$

3) $\frac{a+4+5-a}{9}=\frac{9}{9}=1$

4) $\frac{x+3y+4x+7y}{10}=\frac{5x+10y}{10}=\frac{5(x+2y)}{10}=\frac{x+2y}{2}$

5) $\frac{5m-2-(m-10)}{8m}=\frac{4m+8}{8m}=\frac{4(m+2)}{8m}=\frac{m+2}{2m}$

6) $\frac{7a+13+17-a}{6a}=\frac{6a+30}{6a}=\frac{6(a+5)}{6a}=\frac{a+5}{a}$

1) $\frac{7a}{4x}-\frac{3a}{4x} = \frac{7a-3a}{4x} = \frac{4a}{4x} = \frac{a}{x}$

2) $\frac{x+y}{8}-\frac{x-3y}{8} = \frac{x+y-(x-3y)}{8} = \frac{x+y-x+3y}{8} = \frac{4y}{8} = \frac{y}{2}$

3) $\frac{a+4}{9}+\frac{5-a}{9} = \frac{a+4+5-a}{9} = \frac{9}{9}=1$

4) $\frac{x+3y}{10}+\frac{4x+7y}{10} = \frac{x+3y+4x+7y}{10} = \frac{5x+10y}{10} = \frac{5(x+2y)}{10} = \frac{x+2y}{2}$

5) $\frac{5m-2}{8m}-\frac{m-10}{8m} = \frac{5m-2-(m-10)}{8m} = \frac{5m-2-m+10}{8m} = \frac{4m+8}{8m} = \frac{4(m+2)}{8m} = \frac{m+2}{2m}$

6) $\frac{7a+13}{6a}+\frac{17-a}{6a} = \frac{7a+13+17-a}{6a} = \frac{6a+30}{6a} = \frac{6(a+5)}{6a} = \frac{a+5}{a}$